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tinderbox
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On being stupid in public
Tuesday, January 10, 2006

As several people have already pointed out, I was being silly and letting the surface similarity between constantly's implicit definition and the lambda form confuse me. In the expression with constantly, the *a* is evaluated so that the function constantly can be called. Constantly, in other words, never sees *a*, it just sees 1.

Man, yesterday Bill Clementson talks me up (thanks by the way); today, I stick me foot in my mouth. It didn't even taste good. Oh well. Them's the blogging breaks.


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